#include <bits/stdc++.h>
#define MAX 300010
#define INF LLONG_MAX
#define MOD 1000000007
#define mp make_pair
#define mt make_tuple
#define pb push_back
#define ins insert
#define ff first
#define ss second
#define gett(x,m) get<m>(x)
#define all(a) a.begin(),a.end()
#define lb(a,b) lower_bound(all(a),b)
#define ub(a,b) upper_bound(all(a),b)
#define sortv(a) sort(all(a))
#define sorta(a,sz) sort(a,a+sz)
#define inputar(a,b){\
for(int i=0;i<b;i++){\
cin >> a[i];\
}\
}
#define inputvec(a,b){\
for(int i=0;i<b;i++){\
ll num;\
cin >> num;\
a.pb(num);\
}\
}
#define outputar(a,b){\
for(int i=0;i<b;i++){\
cout << a[i] << " ";\
}\
cout << "\n";\
}
#define outputvec(a){\
for(auto x:a){\
cout << x << " ";\
}\
cout << "\n";\
}
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef tuple<ll,ll,ll> tll;
typedef pair<ll,ll> pll;
inline void USACO(string filename){
freopen((filename+".in").c_str(),"r",stdin);
freopen((filename+".out").c_str(),"w",stdout);
}
ll n,q,t=1,r,m,n2,m2,k,cnt=0,a[MAX],b[MAX],x,y,z,x2,y2,z2,res1=0;
ll c[501][501];
double db;
ll fact[MAX];
ll inv_fact[MAX];
//char c;
string str[MAX];
string s1,s2;
vector<tuple<ll,ll,ll>> v;
vector<pll> v1,v2;
const int mod = 998244353;
ll modmul(ll x,ll y,ll md){
if(y==1){
return x;
}
if(y%2){
return (x+modmul(x,y-1,md))%md;
}
else{
return (modmul((x+x)%md,y/2,md))%md;
}
}
ll powmod(ll x,ll y,ll md){
x%=md;
if(x==0){
return 0;
}
ll res=1;
while(y){
if(y%2==1){
//res=modmul(res,x,md);
res*=x;
res%=MOD;
y--;
}
else{
//x=modmul(x,x,md);
x*=x;
x%=MOD;
y/=2;
}
}
return res;
}
ll pow2(ll x,ll y){
if(x==0){
return 0;
}
ll res=1;
while(y>0){
if(y%2==1){
res*=x;
}
x*=x;
y/=2;
}
return res;
}
ll inv(ll n,ll md){
return powmod(n,md-2,md);
}
ll nCkm(ll n,ll k,ll md){
if(n-k<0){
return 0;
}
return fact[n]*inv_fact[k]%md*inv_fact[n-k]%md;
}
ll nCk(ll x,ll y){
if(x<y){
return 0;
}
ll res=1;
if(y>x-y){
for(int i=y+1;i<=x;i++){
res*=i;
}
for(int i=2;i<=x-y;i++){
res/=i;
}
}
else{
for(int i=x-y+1;i<=x;i++){
res*=i;
}
for(int i=2;i<=y;i++){
res/=i;
}
}
return res;
}
ll countbits(ll x){
ll cnt=0;
while(x){
cnt+=x&1;
x>>=1;
}
return cnt;
}
ll gcd(ll x,ll y){
if(y==0){
return x;
}
return gcd(y,x%y);
}
ll lcm(ll x,ll y){
return x*y/gcd(x,y);
}
bool alpha(char c1,char c2){
ll h1,h2;
if(c1>='a'){
h1=c1-'a';
}
else{
h1=c1-'A';
}
if(c2>='a'){
h2=c2-'a';
}
else{
h2=c2-'A';
}
if(h1==h2){
return c1<c2;
}
else{
return h1<h2;
}
}
ll dx[4]={0,0,1,1};
ll dy[4]={0,1,0,1};
struct custom_hash {
static uint64_t splitmix64(uint64_t x) {
x += 0x9e3779b97f4a7c15;
x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;
x = (x ^ (x >> 27)) * 0x94d049bb133111eb;
return x ^ (x >> 31);
}
size_t operator()(uint64_t x) const {
static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();
return splitmix64(x + FIXED_RANDOM);
}
};
bool ok=true;
vector<vector<ll>> g(MAX);
vector<ll> used(MAX,0);
ll dfs(ll v){
ll cnt=1;
used[v]=1;
for(auto x:g[v]){
if(!used[x]){
cnt+=dfs(x);
}
}
used[v]=2;
return cnt;
}
ll f(vector<pll>& v1){
ll res=0;
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
ll cnt=0;
if(v1[j].ff>=v1[i].ff && v1[j].ff<=v1[i].ss){
cnt++;
}
if(v1[j].ss>=v1[i].ff && v1[j].ss<=v1[i].ss){
cnt++;
}
if(cnt==1){
res++;
}
}
}
return res;
}
void solve(){
cin >> n >> k;
vector<pll> v1(n);
set<ll> st;
for(int i=1;i<=2*n;i++){
st.ins(i);
}
for(int i=0;i<k;i++){
cin >> x >> y;
if(x>y){
swap(x,y);
}
v1[i]=mp(x,y);
st.erase(x);
st.erase(y);
}
ll h=(n-k)*2;
vector<ll> vec(h+1);
ll cnt=0;
for(auto x:st){
vec[cnt]=x;
cnt++;
}
h/=2;
for(int i=0;i<h;i++){
v1[k+i]=mp(vec[i],vec[h+i]);
}
ll res=f(v1);
cout << res/2 << "\n";
}
int main(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> t;
ll cnt1=1;
while(t--){
solve();
cnt1++;
}
}
/*
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
ifstream fin("template.in");
ofstream fout("template.out");
*/
/*
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
ifstream fin("template.in");
ofstream fout("template.out");
*/
/*
ll b[51][51];
b[0][0] = 1;
for (int n = 1; n <= 50; ++n){
b[n][0] = b[n][n] = 1;
for (int k = 1; k < n; ++k)
b[n][k] = b[n - 1][k - 1] + b[n - 1][k];
}
*/
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